Question

Answer 1

a: \(VT=\sqrt{6^2-\left(\sqrt{35}\right)^2}=\sqrt{36-35}=1=VP\)

b: \(\left(\sqrt{4}-\sqrt{3}\right)^2=4+3-2\cdot\sqrt{4\cdot3}\)

\(=7-2\sqrt{12}\)

\(=\sqrt{49}-\sqrt{48}\)