H24
H9
1 tháng 9 2023 lúc 13:43

a) \(A=4\sqrt{\dfrac{25x}{4}}-\dfrac{8}{3}\sqrt{\dfrac{9x}{4}}-\dfrac{4}{3x}\sqrt{\dfrac{9x^3}{64}}\)

\(A=4\cdot\dfrac{\sqrt{25x}}{\sqrt{4}}-\dfrac{8}{3}\cdot\dfrac{\sqrt{9x}}{\sqrt{4}}-\dfrac{4}{3x}\cdot\dfrac{\sqrt{9x^3}}{\sqrt{64}}\)

\(A=4\cdot\dfrac{5\sqrt{x}}{2}-\dfrac{8}{3}\cdot\dfrac{3\sqrt{x}}{2}-\dfrac{4}{3x}\cdot\dfrac{3x\sqrt{x}}{8}\)

\(A=2\cdot5\sqrt{x}-4\sqrt{x}-\dfrac{4\sqrt{x}}{8}\)

\(A=10\sqrt{x}-4\sqrt{x}-\dfrac{\sqrt{x}}{2}\)

\(A=\dfrac{2\cdot6\sqrt{x}-\sqrt{x}}{2}\)

\(A=\dfrac{11\sqrt{x}}{2}\)

b) \(B=\dfrac{y}{2}+\dfrac{3}{4}\sqrt{1-4y+4y^2}-\dfrac{3}{2}\)

\(B=\dfrac{y}{2}-\dfrac{3}{2}+\dfrac{3}{4}\sqrt{1^2-2\cdot1\cdot2y+\left(2y\right)^2}\)

\(B=\dfrac{y-3}{2}+\dfrac{3}{4}\sqrt{\left(1-2y\right)^2}\)

\(B=\dfrac{y-3}{2}+\dfrac{3}{4}\left|1-2y\right|\)

\(B=\dfrac{y-3}{2}+\dfrac{3\left(1-2y\right)}{4}\)

\(B=\dfrac{2y-6+3-6y}{4}\)

\(B=\dfrac{-3-4y}{4}\)

\(B=\dfrac{-3}{4}-\dfrac{4y}{4}\)

\(B=-y-\dfrac{3}{4}\)

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NT
1 tháng 9 2023 lúc 13:36

a: \(A=4\cdot\dfrac{5\sqrt{x}}{2}-\dfrac{8}{3}\cdot\dfrac{3}{2}\sqrt{x}-\dfrac{4}{3x}\cdot\dfrac{3x\sqrt{x}}{8}\)

\(=10\sqrt{x}-4\sqrt{x}-\dfrac{1}{2}\sqrt{x}=\dfrac{11}{2}\sqrt{x}\)

b: B\(=\dfrac{y}{2}+\dfrac{3}{4}\left|2y-1\right|-\dfrac{3}{2}\)

=1/2y+3/4(1-2y)-3/2(Vì y<=1/2)

=1/2y-3/2+3/4-3/2y

=-y-3/4

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