Question

Answer 1

`b,`

`2x(x-5)-3x+15=0`

`-> 2x(x-5)-3(x-5)=0`

`-> (2x-3)(x-5)=0`

`->`\(\left[{}\begin{matrix}2x-3=0\\x-5=0\end{matrix}\right.\)

`->`\(\left[{}\begin{matrix}2x=3\\x=5\end{matrix}\right.\)

`->`\(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=5\end{matrix}\right.\)

Vậy, `x={5; 3/2}`

Answer 2

x=\(\left\{{}5;\begin{matrix}\dfrac{3}{2}\\\end{matrix}\right.\)