Bài 4:
Theo đề, ta có hệ pt:
\(\left\{{}\begin{matrix}a\cdot0^2+b\cdot0+c=4\\a+b+c=7\\a-b+c=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}c=4\\a+b=3\\a-b=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}c=4\\a=4.5\\b=1.5\end{matrix}\right.\)