\(\dfrac{2}{3}\left(x-\dfrac{9}{4}\right)=\dfrac{3}{7}.\dfrac{41}{6}-\dfrac{1}{3}\\ \dfrac{2}{3}\left(x-\dfrac{9}{4}\right)=\dfrac{41}{14}-\dfrac{1}{3}\\ \dfrac{2}{3}\left(x-\dfrac{9}{4}\right)=\dfrac{109}{42}\\ x-\dfrac{9}{4}=\dfrac{109}{28}\\ x=\dfrac{109}{28}+\dfrac{9}{4}\\ x=\dfrac{43}{7}\)
=>2/3(x-9/4)=109/42
=>x-9/4=109/28
=>x=43/7