Question

Answer 1

4) \(\Rightarrow\left(3x+7\right)\left(x+5\right)-\left(x+5\right)\left(3-2x\right)=0\)

\(\Rightarrow\left(x+5\right)\left(5x-4\right)=0\Rightarrow\left[{}\begin{matrix}x=-5\\x=\dfrac{4}{5}\end{matrix}\right.\)

5) \(\Rightarrow2x\left(x-3\right)\left(x+3\right)-5\left(x-3\right)\left(x+3\right)=0\)

\(\Rightarrow\left(x-3\right)\left(x+3\right)\left(2x-5\right)=0\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\\x=\dfrac{5}{2}\end{matrix}\right.\)