\(\Leftrightarrow\dfrac{1}{3}:\left|2x-1\right|=\dfrac{4}{3}-\dfrac{1}{2}=\dfrac{5}{6}\)
\(\Leftrightarrow\left|2x-1\right|=\dfrac{1}{3}:\dfrac{5}{6}=\dfrac{1}{3}\cdot\dfrac{6}{5}=\dfrac{2}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=\dfrac{2}{5}\\2x-1=-\dfrac{2}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{10}\\x=\dfrac{3}{10}\end{matrix}\right.\)
\(\dfrac{4}{3}-\dfrac{1}{3}:\left|2x-1\right|=\dfrac{1}{2}\)
\(\dfrac{1}{3}:\left|2x-1\right|=\dfrac{4}{3}+\dfrac{-1}{2}=\dfrac{5}{6}\)
\(\left|2x-1\right|=\dfrac{1}{3}.\dfrac{6}{5}=\dfrac{2}{5}\)
\(\text{Vậy}2x-1=\dfrac{2}{5}\)
\(2x\) \(=\dfrac{2}{5}+1=\dfrac{7}{5}\)
\(x=\dfrac{7}{5}.\dfrac{1}{2}=\dfrac{7}{10}\)
\(\text{hoặc}\)\(2x-1=\dfrac{-2}{5}\)
\(2x\) \(=\dfrac{-2}{5}+1=\dfrac{3}{5}\)
\(x\) \(=\dfrac{3}{5}.\dfrac{1}{2}=\dfrac{3}{10}\)
\(\text{Hok tốt!}\)