Question

Answer 1

ĐKXĐ : \(\left\{{}\begin{matrix}x\ne0\\x\ne-1\end{matrix}\right.\)

PT \(\Leftrightarrow\dfrac{\left(x-1\right)\left(x+1\right)}{x\left(x+1\right)}+\dfrac{x}{x\left(x+1\right)}=\dfrac{2x-1}{2x^2+2}\)

\(\Leftrightarrow\dfrac{\left(x-1\right)\left(x+1\right)+x}{x\left(x+1\right)}=\dfrac{2x-1}{2x^2+2}\)

\(\Leftrightarrow\left(x^2-1+x\right)\left(2x^2+2\right)=\left(2x-1\right)\left(x^2+x\right)\)

\(\Leftrightarrow2x^4-2x^2+2x^3+2x^2-2+2x=2x^3-x^2+2x^2-x\)

\(\Leftrightarrow2x^4-2x^2+2x^3+2x^2-2+2x-2x^3+x^2-2x^2+x=0\)

\(\Leftrightarrow2x^4-x^2+3x-2=0\)

( :vvvv đề có sai hay nhầm không mà ra vô tỉ :vv )

Answer 2

(x−1)(x+1)+xx(x+1)=2x−12x2+2⇔(x−1)(x+1)+xx(x+1)=2x−12x2+2

$tương\; đương\; ({}^{}-1+x)\left(2{}^{}+2\right)$