Question

Answer 1

Giúp em vs nha mng. Cảm ơn ạ!

Answer 2

a: AC⊥AB

BM⊥AB

Do đó: AC//BM

Answer 3

a, Vì AC⊥AB và BM⊥AB nên AC//BM

b, Ta có \(\widehat{DME}=90^0-\widehat{DEM}=30^0;\widehat{AMB}=90^0-\widehat{MAB}=60^0\)

Do đó \(\widehat{BMC}=\widehat{AMB}+\widehat{ACM}=30^0+\widehat{DME}=90^0\)

\(\Rightarrow CM\perp BM\\ \Rightarrow CM\perp AC\\ \Rightarrow AC//DE\)