Question

Answer 1

\(B=\dfrac{2\sqrt{x}-\sqrt{x}-3}{x+3\sqrt{x}}.\dfrac{x+3\sqrt{x}}{\sqrt{x}-2}\)

\(B=\dfrac{\sqrt{x}-3}{\sqrt{x}-2}\)

Answer 2

a) Ta có: \(B=\left(\dfrac{2}{\sqrt{x}+3}-\dfrac{1}{\sqrt{x}}\right):\dfrac{\sqrt{x}-2}{x+3\sqrt{x}}\)

\(=\dfrac{2\sqrt{x}-\sqrt{x}-3}{\sqrt{x}\left(\sqrt{x}+3\right)}\cdot\dfrac{\sqrt{x}\left(\sqrt{x}+3\right)}{\sqrt{x}-2}\)

\(=\dfrac{\sqrt{x}-3}{\sqrt{x}-2}\)