Bài 2:
a) Ta có: \(\dfrac{x}{27}=\dfrac{-2}{3.6}\)
\(\Leftrightarrow x=\dfrac{-2\cdot27}{3.6}=\dfrac{-54}{3.6}=-15\)
b) Ta có: \(-0.52:x=-9.36:16.8\)
\(\Leftrightarrow\dfrac{-0.52}{x}=\dfrac{-9.36}{16.8}\)
\(\Leftrightarrow x=\dfrac{-0.52\cdot16.8}{-9.36}=\dfrac{14}{15}\)