Nghiệm của phương trình \(\dfrac{2}{3}x+\dfrac{1}{2}=-\dfrac{1}{2}x+1\) là
\(x=\dfrac{3}{7}\).\(x=-\dfrac{3}{7}\).\(x=\dfrac{4}{7}\).\(x=\dfrac{1}{3}\).Hướng dẫn giải:\(\dfrac{2}{3}x+\dfrac{1}{2}=-\dfrac{1}{2}x+1\)
\(\Leftrightarrow\dfrac{2}{3}x+\dfrac{1}{2}x=1-\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{7}{6}x=\dfrac{1}{2}\)
\(\Leftrightarrow x=\dfrac{1}{2}:\dfrac{7}{6}\)
\(\Leftrightarrow x=\dfrac{3}{7}\)
