Các câu hỏi tương tự
GIẢI PT SAU:
\(\sqrt{3x-3}-\sqrt{5-x}=\sqrt{2x-4}\)
\(x^2-6x+9=4\sqrt{x^2-6x+6}\)
\(x^2-x+8-4\sqrt{x^2-x+4}=0\)
GIẢI PT SAU:
\(\sqrt{3x-3}-\sqrt{5-x}=\sqrt{2x-4}\)
\(x^2-6x+9=4\sqrt{x^2-6x+6}\)
Giải pt:
\(\sqrt{x^2+10x+21}=3\sqrt{x+3}+2\sqrt{x+7}-6\)
\(4\left(x+1\right)^2=\left(2x+10\right)\left(1-\sqrt{3+2x}\right)^2\)
\(\frac{1}{1-\sqrt{1-x}}-\frac{1}{1+\sqrt{1-x}}=\frac{\sqrt{3}}{x}\)
\(\sqrt{x+3}+2x\sqrt{x+1}=2x+\sqrt{x^2+4x+3}\)
\(\sqrt{x-2}+\sqrt{4-x}=x^2-6x+11\)
GIẢI CÁC PT SAU:
\(\sqrt{5x+10}=8-x\)
\(\sqrt{4x^2+x-12}=3x-5\)
\(\sqrt{x^2-2x+6}=2x-3\)
\(\sqrt{3x^2-2x+6}+3-2x=0\)
\(\left\{{}\begin{matrix}\sqrt{x+y}=2+\sqrt{x-y}\\\sqrt{x^2+y^2+1}-\sqrt{x^2-y^2}=-6x-3y\end{matrix}\right.\)
\(\sqrt{2x^2-6x+8}-\sqrt{x}\le x-2\)
xác định hàm số a, ysqrt{x^2+x-4}b , yfrac{1}{x^2+1}c, y l 2x - 3 l d , yfrac{1}{x^2-3x}e , ysqrt{1-x}+frac{1}{xsqrt{1}+x}f , yfrac{2x-1}{sqrt{xsqrt{left(x-4right)}}}g , ysqrt{3+x}+frac{1}{x^2-1}h , yfrac{1}{sqrt{2x^2-4x+4}}i, ysqrt{6-x}+2xsqrt{2x+1}j, yfrac{x^2+1}{sqrt{2-5}}+xsqrt{1+x}k, yfrac{1}{x^2+3x+3}+left(x+2right)sqrt{x+3}l, ysqrt[3]{frac{3x+5}{x^2-1}}
Đọc tiếp
xác định hàm số
a, \(y=\sqrt{x^2+x-4}\)
b , \(y=\frac{1}{x^2+1}\)
c, y= l 2x - 3 l
d , \(y=\frac{1}{x^2-3x}\)
e , \(y=\sqrt{1-x}+\frac{1}{x\sqrt{1}+x}\)
f , \(y=\frac{2x-1}{\sqrt{x\sqrt{\left(x-4\right)}}}\)
g , \(y=\sqrt{3+x}+\frac{1}{x^2-1}\)
h , \(y=\frac{1}{\sqrt{2x^2-4x+4}}\)
i, \(y=\sqrt{6-x}+2x\sqrt{2x+1}\)
j, \(y=\frac{x^2+1}{\sqrt{2-5}}+x\sqrt{1+x}\)
k, \(y=\frac{1}{x^2+3x+3}+\left(x+2\right)\sqrt{x+3}\)
l, \(y=\sqrt[3]{\frac{3x+5}{x^2-1}}\)
tìm TXĐ của hàm số:
a) y=\(\dfrac{\sqrt{x^2-x+1}}{x-3}\)
b)y=\(\dfrac{\sqrt{5-2x}}{\left(x-2\right)\sqrt{x-1}}\)
\(\sqrt{-x^2+6x-5}>8-2x\)