\(\dfrac{5}{7}y-\dfrac{5}{7}+\dfrac{3}{4}=\dfrac{21}{28}\)
\(\Rightarrow\dfrac{5}{7}y-\dfrac{5}{7}+\dfrac{3}{4}=\dfrac{3}{4}\)
\(\Rightarrow\dfrac{5}{7}y=\dfrac{3}{4}+\dfrac{5}{7}-\dfrac{3}{4}\)
\(\Rightarrow\dfrac{5}{7}y=\dfrac{5}{7}\)
\(\Rightarrow y=1\)
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Ta có: \(y\cdot\dfrac{5}{7}-\dfrac{5}{7}+\dfrac{3}{4}=\dfrac{21}{28}\)
\(\Leftrightarrow y\cdot\dfrac{5}{7}-\dfrac{5}{7}=0\)
hay y=1
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