=>x(y-3)+y-3=2
=>(x+1)(y-3)=2
\(\Leftrightarrow\left(x+1;y-3\right)\in\left\{\left(1;2\right);\left(2;1\right);\left(-1;-2\right);\left(-2;-1\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(0;5\right);\left(1;4\right);\left(-2;1\right);\left(-3;2\right)\right\}\)
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