Question

(x+3)^2-1/3=1/9

 

Answer 1

Ta có: \(\left(x+3\right)^2-\dfrac{1}{3}=\dfrac{1}{9}\)

\(\Leftrightarrow\left(x+3\right)^2=\dfrac{4}{9}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+3=\dfrac{2}{3}\\x+3=\dfrac{-2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-7}{3}\\x=\dfrac{-11}{3}\end{matrix}\right.\)

Vậy: \(x\in\left\{-\dfrac{7}{3};-\dfrac{11}{3}\right\}\)

Answer 2

\(\left(x+3\right)^2-\dfrac{1}{3}=\dfrac{1}{9}\Leftrightarrow\left(x+3\right)^2=\dfrac{1}{9}+\dfrac{1}{3}=\dfrac{4}{9}\)

TH1 : \(x+3=\dfrac{2}{3}\Leftrightarrow x=\dfrac{2}{3}-3=\dfrac{2}{3}-\dfrac{9}{3}=-\dfrac{7}{3}\)

TH2 : \(x+3=-\dfrac{2}{3}\Leftrightarrow x=-\dfrac{2}{3}-\dfrac{9}{3}=-\dfrac{11}{3}\)

Answer 3

Giải:

(x+3)²-1/3=1/9

(x+3)²       =1/9+1/3

(x+3)²       =4/9

=>(x+3)²   =(2/3)²

=>x+3       =2/3

        x       =2/3-3

        x       =-7/3

Chúc bạn học tốt!

Answer 4

Làm tiếp:

+)TH2:

=>(x+3)² = (-2/3)²

x+3         = -2/3

    x         =-2/3-3

    x        =-11/3

Đầy đủ rồi nhé!

Answer 5

ngu

Answer 6

(x+3)^2-1/3=1/9

(x+3)^2=1/9+1/3

(x+3)^2=4/9

(x+3)^2=(2/3)^2

⇒x+3=2/3

*TH1:x+3=2/3                                                        *TH2:x+3=-2/3

          x=2/3-3                                                                 x=-2/3-3          x=-7/3                                                                   x=-11/3