\(x+3x\cdot\left(102-3,33\right)=115\)\(\Rightarrow x+306x-9,99x=115\)\(\Rightarrow x\cdot\left(1+306-9,99\right)=105\)\(\Rightarrow x\cdot297,01=105\)\(\Rightarrow x=\dfrac{105}{297,01}\)\(\Rightarrow x=\dfrac{1500}{4243}\)Câu trả lời: \(x+3x\cdot\left(102-3,33\right)=115\)\(\Rightarrow x+306x-9,99x=115\)\(\Rightarrow x\cdot\left(1+306-9,99\right)=105\)\(\Rightarrow x\cdot297,01=105\)\(\Rightarrow x=\dfrac{105}{297,01}\)\(\Rightarrow x=\dfrac{1500}{4243}\)