\(=x^3-x^2+3x^2-3x^2+x-1=\left(x-1\right)\left(x^2+3x+1\right)\)
\(x^3+2x^2-2x-1\)
\(=\left(x-1\right)\left(x^2+x+1\right)+2x\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2+3x+1\right)\)
x3+2x2-2x-1=(x3-1)+(2x2-2x)=(x-1)(x2+x+1)+2x(x-1)=(x-1)[(x2+x+1)+2x]=(x-1)(x2+x+1+2x)=(x-1)(x2+3x+1)