Question

x+2/x+1+3/x-2=3/x^2-x-2+1 giúp mk với

 

Answer 1

\(\dfrac{x+2}{x+1}+\dfrac{3}{x-2}=\dfrac{3}{x^2-x-2}+1\)

\(\Leftrightarrow3+x^2-x-2=x^2-4+3x+3\)

\(\Leftrightarrow x^2-x+1=x^2+3x-1\)

=>-4x=-2

hay x=1/2(nhận)