Question

(x+2)^2-(x-2)(x+1)=3

Answer 1

\(\left(x+2\right)^2-\left(x-2\right)\left(x+1\right)=3\\ \Leftrightarrow\left(x^2+4x+4\right)-\left(x^2-2x+x-2\right)=3\\ \Leftrightarrow x^2+4x+4-x^2+x+2=3\\ \Leftrightarrow5x+6=3\\ \Leftrightarrow5x=3-6\\ \Leftrightarrow5x=-3\\ \Leftrightarrow x=-\dfrac{3}{5}\)

Answer 2

\(\left(x+2\right)^2-\left(x-2\right)\left(x+1\right)=3\)

\(\Leftrightarrow x^2+4x+4-\left(x^2-x-2\right)=3\)

\(\Leftrightarrow x^2+4x+4-x^2+x+2=3\)

\(\Leftrightarrow\left(x^2-x^2\right)+\left(4x+x\right)+\left(4+2\right)=3\)

\(\Leftrightarrow5x+6=3\)

\(\Leftrightarrow5x=3-6\)

\(\Leftrightarrow5x=-3\)

\(\Leftrightarrow x=\left(-3\right):5\)

\(\Leftrightarrow x=-\dfrac{3}{5}\)