Question

x/2 = y/3 = z/5 ; xyz = 810

Answer 1

Đặt \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}=k\)

=>x=2k; y=3k; z=5k

xyz=810

=>\(2k\cdot3k\cdot5k=810\)

=>\(30k^3=810\)

=>\(k^3=27=3^3\)

=>k=3

\(x=2\cdot3=6;y=3\cdot3=9;z=5\cdot3=15\)

Answer 2

Đặt:x=2k,y=3k,z=5k

=> (2k)(3k)(5k)=810

=> 30k^3 = 810

=> k^3 = 810 / 30 = 27

=> k = căn bậc 3 của 27 

=> k = 3

x = 2k => x = 6

y = 3k => y= 9

z = 5k => z= 15

Vậy x=6,y=9,z=15