Question

(x+2) (x-3)-(x+1) (x-4)=5

Answer 1

\(\left(x+2\right)\left(x-3\right)-\left(x+1\right)\left(x-4\right)=5\)

\(\Leftrightarrow x^2-x-6-x^2+3x+4=5\)

\(\Leftrightarrow2x-2=5\)

\(\Leftrightarrow x=\dfrac{7}{2}\)

Vậy \(S=\left\{\dfrac{7}{2}\right\}\)

Answer 2

Ta có: \(\left(x+2\right)\left(x-3\right)-\left(x+1\right)\left(x-4\right)=5\)

\(\Leftrightarrow x^2-x-6-x^2+3x+4=5\)

\(\Leftrightarrow2x-2=5\)

hay \(x=\dfrac{7}{2}\)