Question

x^2 - x +2

x^2 - x +6

phân tích đa thức thành nhân tử 

Answer 1

a,\(x^2-x+2=x^2-2.\dfrac{1}{2}x+\dfrac{1}{4}+\dfrac{7}{4}\\ =\left(x-\dfrac{1}{2}\right)^2+\dfrac{7}{4}\)

\(b,x^2-2.\dfrac{1}{2}x+\dfrac{1}{4}+\dfrac{23}{4}\\ =\left(x-\dfrac{1}{2}\right)^2+\dfrac{23}{4}\)

Answer 2

\(x^2-x-2=\left(x-2\right)\left(x+1\right)\)

\(x^2-x-6=\left(x-3\right)\left(x+2\right)\)