Question

(X²-3x+1)(x²-3x+2)=2

Answer 1

Bạn tham khảo

\((x^2-3x+1)(x^2-3x+2)=2\)

Đặt \(x^2-3x+1,5=y(y \ge-0,75)\)

\(pt \Leftrightarrow(y-0,5)(y+0,5)=2 \)

\(\Leftrightarrow y^2-0,25=2\)

\(\Leftrightarrow y^2=2,25\)

\(\Leftrightarrow \left[\begin{matrix} y=1,5(N)\\ y=-1,5(L)\end{matrix}\right.\)
Với \(y=1,5 \Rightarrow x^2-3x+1,5=1,5\)

\(\Leftrightarrow x(x-3)=0\)

\(\Leftrightarrow \left[\begin{matrix} x=0\\ x=3\end{matrix}\right.\)

Vậy \(\text{S={0;3}}\)

Answer 2

Đề yêu cầu gì đó em?