Ta có: \(\dfrac{x+1}{x-2}+\dfrac{-x}{x+2}+\dfrac{2+3x}{4-x^2}\)
\(=\dfrac{x+1}{x-2}-\dfrac{x}{x+2}-\dfrac{3x+2}{\left(x-2\right)\left(x+2\right)}\)
\(=\dfrac{\left(x+1\right)\left(x+2\right)-x\left(x-2\right)-3x-2}{\left(x-2\right)\left(x+2\right)}\)
\(=\dfrac{x^2+3x+2-x^2+2x-3x-2}{\left(x-2\right)\left(x+2\right)}=\dfrac{2x}{\left(x-2\right)\left(x+2\right)}\)