|x+1/3|-5=-2
=>\(\left|x+\dfrac{1}{3}\right|=-2+5=3\)
=>\(\left[{}\begin{matrix}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{matrix}\right.\)
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