` X xx 2 + x/2 = 10`
` X xx ( 2 + 1/2) = 10`
` X xx 5/2 = 10`
` X = 10 : 5/2`
` X = 10 xx 2/5`
` X = 4`
Vậy `X = 4`
2x + x/2 = 10
=> x ( 2 + 1/2) = 10
=> x ( 4/2 + 1/2 ) = 10
=> 5/2 x =10
=> x= 10 : 5/2
=> x = 4
=> \(x\) x (2+ 1/2) = 10
=> x = 10: 5/2
=> x = 4