\(\left(x+5\right)^3=\dfrac{-64}{125}\)
\(\Rightarrow\left(x+5\right)^3=\left(\dfrac{-4}{5}\right)^3\)
\(\Rightarrow x+5=-\dfrac{4}{5}\)
\(\Rightarrow x=-\dfrac{4}{5}-5\)
\(\Rightarrow x=-\dfrac{29}{5}\)
\(\left(x+5\right)^3=\dfrac{-64}{125}\)
\(\Rightarrow\left(x+5\right)^3=\left(\dfrac{-4}{5}\right)^3\)
\(\Rightarrow x+5=-\dfrac{4}{5}\)
\(\Rightarrow x=-\dfrac{4}{5}-5\)
\(\Rightarrow x=-\dfrac{29}{5}\)
(3/5-2/3.x)3=-64/125
(5^4-5^3)^3/125^4-64/125
Tìm x, biết:
a) \(\dfrac{2}{3}\)x - \(\dfrac{1}{2}\)x = \(\left(-\dfrac{7}{12}\right)\) . \(1\dfrac{2}{5}\)
b) \(\left(\dfrac{1}{5}-\dfrac{3}{2}x\right)^2\) = \(\dfrac{9}{4}\)
c) (1,25 - \(\dfrac{4}{5}\)x)3 = -125
(5^4-5^3/125^4)=64/125
\(\left(x-\dfrac{2}{15}\right)^3=\dfrac{8}{125};\left(\dfrac{4}{5}\right)^{2x+5}=\dfrac{256}{625}\)
17)\(\dfrac{\left(x+3\right)^5}{\left(x+3\right)^2}=\dfrac{64}{27}\)
\(\left(\frac{3}{5}-\frac{2}{3}x\right)^3=-\frac{64}{125}\)
Tìm x, biết \(\dfrac{1}{4}.\dfrac{2}{6}.\dfrac{3}{8}.\dfrac{4}{10}.\dfrac{5}{12}...\dfrac{30}{62}.\dfrac{31}{64}=2^x\)
(54-53)3/1254 - 64/125