\(x-\dfrac{2x-5}{5}+\dfrac{x+2}{6}=7+\dfrac{x-1}{3}\)
=>\(\dfrac{30x-6\left(2x-5\right)+5\left(x+2\right)}{30}=\dfrac{210+10\left(x-1\right)}{30}\)
=>30x-12x+30+5x+10=210+10x-10
=>23x+40=10x+200
=>13x=160
=>x=160/13
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