ĐKXĐ: x>=1
\(x-2\sqrt{x-1}-4=0\)
=>\(x-1-2\sqrt{x-1}-3=0\)
=>\(\left(\sqrt{x-1}\right)^2-2\sqrt{x-1}-3=0\)
=>\(\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)=0\)
=>\(\sqrt{x-1}-3=0\)(Vì \(\sqrt{x-1}+1>=1>0\forall x>=1\))
=>\(\sqrt{x-1}=3\)
=>x-1=9
=>x=10(nhận)