- x -\(\dfrac{2}{3}\)=\(\dfrac{-6}{7}\)
- x =\(\dfrac{-6}{7}\)+\(\dfrac{2}{3}\)=\(\dfrac{-4}{21}\)
Vậy x=...
Ta có: \(-x-\dfrac{2}{3}=-\dfrac{6}{7}\)
\(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{6}{7}\)
hay \(x=\dfrac{4}{21}\)
- x -\(\dfrac{2}{3}\)=\(\dfrac{-6}{7}\)
- x =\(\dfrac{-6}{7}\)+\(\dfrac{2}{3}\)=\(\dfrac{-4}{21}\)
Vậy x=...
Ta có: \(-x-\dfrac{2}{3}=-\dfrac{6}{7}\)
\(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{6}{7}\)
hay \(x=\dfrac{4}{21}\)
1) 17/6 - (x-7/6)=7/4
2) 3/35-(3/5-x)=2/7
3) 2x-3=x+1/2
4) 11/12-(2/5+x)-2/3
( -3/7 ) x 5/11 + ( -3/7 ) x 6/11 + 2 x 3/7
X-3/8=1/6-1/5
-7/10(x+1/3) =4/5
X-4/3=5/6
( -1/2)-3/5=4/6
6/5+(x-2/3)=4/7
Bài 1 thực hiện phép tính 1 cách hợp lí nhất
a)5/3+(-2/7)-(-1,2)
b)-4/9+(-5/6)-17/4
Bài 2 Tìm x,biết
x+1/3=3/4
x-2/5=6/7
-x-2/3=-6/7
4/7-x=1/3
Chung minh:
a/ \(5^5-5^4+5^3⋮\) 7
b/ \(7^6+7^5-7^4⋮11\)
c/ \(3^{x+3}+3^{x+1}+2^{x+3}+3^x-2^{x+1}⋮10\)
d/\(3^{x+3}+3^{x+1}+2^{x+3}+2^{x+2}⋮6\)
tính:
\(a.9^x:3^x=3^7\)
b.\(\frac{1}{2}.2^x+2^{x+2}=2^8+2^5\)
c\(^{7^{x+2}+2.7^{x-1}=345}\)
d \(\left(\frac{1}{2}-\frac{1}{3}\right).6^x+6^{x+2}=6^7+6^4\)
tìm x trong các tỉ lệ thức sau:a,2/7:x=11/6:7/12;
b,2-x/3=-3/x-2
c,x-1/x+2=2/3
(1/2-1/3)*6^x+6^x+2=6^7+6^4
| 7 - 3/4 . x | - 3/2 = 1/1/2
5 - | x - 3 | = 5
| 7/2 - 42 | + 14 = 14
2/3 - | x + 2 | = 2
5/6 . | 3 - x | + 4 = 2
Giải giúp mình với
Bài 1: Tìm x; y ϵ \(ℤ\)
a) 2x - y\(\sqrt{6}\) = 5 + (x + 1)\(\sqrt{6}\)
b) 5x + y - (2x -1)\(\sqrt{7}\) = y\(\sqrt{7}\) + 2
Bài 2: So sánh M và N
M = \(\dfrac{\dfrac{3}{4}+\dfrac{3}{5}+\dfrac{3}{7}-\dfrac{3}{11}}{\dfrac{6}{4}+\dfrac{6}{5}+\dfrac{6}{7}-\dfrac{6}{11}}\)
N = \(\dfrac{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}{\dfrac{6}{2}+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}\)
Bài 3: Chứng minh:
\(\dfrac{1}{2!}+\dfrac{1}{3!}+\dfrac{1}{4!}+...+\dfrac{1}{2023!}< 1\)