ĐKXĐ: \(x\notin\left\{2;-1\right\}\)
\(\dfrac{x+1}{x-2}\cdot\dfrac{x^2-4}{\left(x+1\right)^2}\)
\(=\dfrac{x+1}{x-2}\cdot\dfrac{\left(x-2\right)\left(x+2\right)}{\left(x+1\right)^2}\)
\(=\dfrac{x+2}{x+1}\)
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