\(\Leftrightarrow2x^2+3x-2x-3+2x-2=0\)
\(\Leftrightarrow2x^2+3x-5=0\)
=>(2x+5)(x-1)=0
=>x=-5/2 hoặc x=1
\(\left(x-1\right)\left(2x+3\right)+2x=2\\ \Rightarrow\left(x-1\right)\left(2x+3\right)+2x-2=0\\ \Rightarrow\left(x-1\right)\left(2x+3\right)+2\left(x-1\right)=0\\ \Rightarrow\left(x-1\right)\left(2x+3+2\right)=0\\\Rightarrow \left(x-1\right)\left(2x+5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{5}{2}\end{matrix}\right.\)