\(\sqrt{\dfrac{-2}{x+1}}\)
ĐK : `x+1 <0`
`<=> x<-1`
\(\sqrt{-\dfrac{2}{x+1}}=\dfrac{\sqrt{2}}{\sqrt{-x-1}}\)
\(ĐK:x\le-1\)
\(x\ne-1\)
\(\Rightarrow x< -1\)
\(\sqrt{\dfrac{-2}{x+1}}\)
\(ĐK:\left\{{}\begin{matrix}\dfrac{-2}{x+1}\ge0\\x+1\ne0\end{matrix}\right.\\ \Leftrightarrow x+1< 0\left(\text{vì }-2< 0\right)\\ \Leftrightarrow x< -1\)