Question

Trục căn thức ở mẫu:

\(\dfrac{x+b\sqrt{x}}{b\sqrt{x}}\)

Answer 1

\(=\dfrac{\sqrt{x}\left(b+\sqrt{x}\right)}{b\sqrt{x}}=\dfrac{b+\sqrt{x}}{b}\)

Answer 2

\(=\dfrac{\left(x+b\sqrt{x}\right)\sqrt{x}}{bx}=\dfrac{x\sqrt{x}+bx}{bx}\)