Question

Tính

\(\dfrac{4^7.\left(-18\right)^3}{6^7.\left(-8\right)^2}\)

Answer 1

\(=\dfrac{-2^{14}\cdot2^3\cdot3^6}{2^7\cdot3^7\cdot2^6}=\dfrac{-2^{17}\cdot3^6}{2^{13}\cdot3^7}=\dfrac{-16}{3}\)

Answer 2

`= (-1 xx 2^14 xx 2^3 xx 3^6)/(2^7 xx 3^7 xx 2^6)`

`= (-1 xx 2^17 xx 3^6)/(2^13 xx 3^7)`

`= - (2^4)/3`.

`= -16/3`.

Answer 3

\(=\dfrac{\left(2^2\right)^7.\left[\left(-2\right)^2.3^2\right]^3}{\left(2.3\right)^7.\left[\left(-2\right)^3\right]^2}=\dfrac{2^{14}.2^6.3^6}{2^7.3^7.2^6}=\dfrac{2^{20}.3^6}{2^{13}.3^7}\\ =\dfrac{2^7}{3}=\dfrac{128}{3}\)