Question

tính

\(B=\dfrac{2x+8\sqrt{x}+6}{x-9}+\dfrac{\sqrt{x}-1}{3-\sqrt{x}}\)

Answer 1

\(B=\dfrac{2x+8\sqrt{x}+6-x-2\sqrt{x}+3}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)

\(=\dfrac{\sqrt{x}+3}{\sqrt{x}-3}\)