Question

Tính:

a)  (x²+2x-y²+1):(x-y+1)
b) (hình ảnh)
với x khác -1; x khác 0; x khác 1

Answer 1

a: \(\dfrac{\left(x^2+2x-y^2+1\right)}{x-y+1}\)

\(=\dfrac{\left(x^2+2x+1\right)-y^2}{x+1-y}\)

\(=\dfrac{\left(x+1\right)^2-y^2}{\left(x+1-y\right)}=\dfrac{\left(x+1+y\right)\left(x+1-y\right)}{\left(x+1-y\right)}=x+1+y\)