Question

Tính:

a) \(\left(2x^3+x^2-8x+3\right):\left(2x-3\right)\)

b) \(\dfrac{x-5}{x^2-4x+4}:\dfrac{x^2-25}{2x-4}\)

Answer 1

a: \(=\dfrac{2x^3-3x^2+4x^2-6x-2x+3}{2x-3}=x^2+2x-1\)

b: \(=\dfrac{x-5}{\left(x-2\right)^2}\cdot\dfrac{2\left(x-2\right)}{\left(x-5\right)\left(x+5\right)}=\dfrac{2}{\left(x-2\right)\left(x+5\right)}\)