Question

tính:

a, \(\dfrac{x+1}{x-2}+\dfrac{x-2}{x+1}+\dfrac{14-x}{4-x^2}\)

Answer 1

\(=\dfrac{x^2+2x+1+x^2-4x+4+x-14}{\left(x-2\right)\left(x+2\right)}=\dfrac{2x^2-x-9}{\left(x-2\right)\left(x+2\right)}\)