\(=\dfrac{5.3.1}{7.4.2}=\dfrac{15}{14.4}=\dfrac{15}{56}\)
\(=\dfrac{3.5.14}{4.7.15}=\dfrac{3.5.7.2}{2.2.7.3.5}=\dfrac{1}{2}\)
a; \(=\dfrac{5\cdot3\cdot1}{7\cdot4\cdot2}=\dfrac{15}{56}\)
b: \(=\dfrac{3\cdot5\cdot14}{4\cdot7\cdot15}=\dfrac{210}{420}=\dfrac{1}{2}\)