Question

Tính

117:{[79-3(33 -17)]:7+2}

Answer 1

\(=117:\left[\left(79-3\cdot16\right):7+2\right]=117:\left[\left(79-48\right):7+2\right]\)

=117/5

Answer 2

 

117:{[79-3(33 -17)]:7+2}

 

=117:{[79-3.16]:7+2}

=117:{[79-48]:7+2}

=117:{31:7+2}

=117:{\(\dfrac{31}{7}\)+2}

=117:\(\dfrac{45}{7}\)

=\(\dfrac{91}{5}\)

Answer 3

=117/5