Question

tính (|x|-1).(x²-2)=0

 

Answer 1

\(\Rightarrow\left[{}\begin{matrix}x-1=0\\x^2-2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x^2=2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=\pm\sqrt{2}\end{matrix}\right.\)

Answer 2

\(=>\left[{}\begin{matrix}\left|x\right|-1=0\\x^2-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}\left|x\right|=1\\x^2=2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\pm1\\x=\pm\sqrt{2}\end{matrix}\right.\)