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\(19\dfrac{5}{8}:\dfrac{7}{12}+\left(-15\dfrac{1}{4}\right):\dfrac{7}{12}\)

\(\dfrac{2}{5}.\dfrac{1}{3}-2\dfrac{2}{15}:\dfrac{1}{5}+\dfrac{3}{5}.\dfrac{1}{3}\)

KS
24 tháng 6 2022 lúc 19:57

`19 5/8 : 7/12 + (-15 1/4) : 7/12`

`= 157/8 xx 12/7 + (-61/4) xx 12/7`

`= [157/8 + (-61/4)] xx 12/7`

`= 35/8 xx 12/7`

`= 15/2`

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`2/5 . 1/3 - 2 2/15 : 1/5 + 3/5 . 1/3`

`= 2/5 . 1/3 + 3/5 . 1.3 - 32/15 : 1/5`

`= (2/5 + 3/5) . 1/3 - 32/15 xx 5`

`= 1 . 1/3 - 32/15 xx5`

`= 1/3 - 32/3`

`= -31/3`

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DL
24 tháng 6 2022 lúc 19:58

a/

=\(\dfrac{157}{8}.\dfrac{12}{7}-\dfrac{61}{4}.\dfrac{12}{7}=\left(\dfrac{157}{8}-\dfrac{61}{4}\right).\dfrac{12}{7}=\dfrac{35}{8}.\dfrac{12}{7}\)

\(=\dfrac{15}{2}\)

b/

\(=\left(\dfrac{2}{5}+\dfrac{3}{5}\right).\dfrac{1}{3}-\dfrac{32}{15}.5=1.\dfrac{1}{3}-\dfrac{32}{3}=\dfrac{1}{3}-\dfrac{32}{3}=-\dfrac{31}{3}\)

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H24
24 tháng 6 2022 lúc 19:58

\(19\dfrac{5}{8}:\dfrac{7}{12}+\left(-15\dfrac{1}{4}\right):\dfrac{7}{12}=\dfrac{157}{8}:\dfrac{7}{12}+\left(-\dfrac{61}{4}\right):\dfrac{7}{12}=\left\{\dfrac{157}{8}+\left(-\dfrac{61}{4}\right)\right\}:\dfrac{7}{12}=\dfrac{15}{2}\)

\(\dfrac{2}{5}.\dfrac{1}{3}-2\dfrac{2}{15}:\dfrac{1}{5}+\dfrac{3}{5}.\dfrac{1}{3}=\dfrac{2}{5}.\dfrac{1}{3}-\dfrac{32}{15}:\dfrac{1}{5}+\dfrac{3}{5}.\dfrac{1}{3}=\left(\dfrac{2}{5}+\dfrac{3}{5}\right).\dfrac{1}{3}-\dfrac{32}{15}:\dfrac{1}{5}=\dfrac{1}{3}-\dfrac{32}{15}:\dfrac{1}{5}=-\dfrac{31}{3}\)

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H24
24 tháng 6 2022 lúc 19:59

`19 5/8 : 7/12 +(-15 1/4):7/12`

`=[19 5/8 + (-15 1/4) :7/12`

`=[157/8+ (-59/4)]:7/12`

`=[157/8+(-118/8)]xx12/7`

`=39/8 xx 12/7`

`=117/14`

`---------`

`2/5  .1/3 - 2 2/15 : 1/5 + 3/5 . 1/3`

`=2/5 .1/3 -  32/15 : 1/5 + 3/5 . 1/3`

`=2/5 .1/3 -  32/15 .  5 + 3/5 . 1/3`

`=2/5 .1/3 -  32/3 + 3/5 . 1/3`

`=(2/5+3/5). 1/3 -32/3`

`=1 . 1/3 -32/3`

`=1/3 - 32/3`

`=-31/3`

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DD
24 tháng 6 2022 lúc 20:04

\(=\dfrac{157}{8}:\dfrac{7}{12}-\dfrac{61}{4}:\dfrac{7}{12}\)

\(=\left(\dfrac{157}{8}-\dfrac{61}{4}\right):\dfrac{7}{12}\)

\(=\dfrac{35}{8}:\dfrac{7}{12}\)

\(=\dfrac{15}{2}\)

\(\dfrac{2}{5}.\dfrac{1}{3}-\dfrac{32}{15}:\dfrac{1}{5}+\dfrac{3}{5}.\dfrac{1}{3}\)

\(=\dfrac{2}{5}.\dfrac{1}{3}-\dfrac{32}{15}.5+\dfrac{3}{5}.\dfrac{1}{3}\)

\(=\dfrac{1}{3}\left(\dfrac{2}{5}+\dfrac{3}{5}\right)-\dfrac{32}{3}\)

\(=\dfrac{1}{3}.1-\dfrac{32}{3}\)

\(=\dfrac{1}{3}-\dfrac{31}{3}\)

\(=\dfrac{-30}{3}=-10\)

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