Ta có
n\(_{N2O}=\frac{1,12}{22,4}=0,05\left(mol\right)\)
m\(_{N2O}=0,05.44=2,2\left(g\right)\)
n\(_{SO2}=\frac{2,24}{22,4}=0,1\left(mol\right)\)
m\(_{SO2}=0,1.64=6,4\left(g\right)\)
n\(_{Cl2}=\frac{2,688}{22,4}=0,12\left(mol\right)\)
m\(_{Cl2}=0,12.71=8,52\left(g\right)\)
Chúc bạn học tốt
*11,2 l N2O
Ta có n N2O= 0,05(mol)
=>m N2O= 0,05. 44= 2,2(g)
*2,24l SO2
Ta có n SO2= 0,1 (mol)
=>mSO2= 0,1 . 64= 6,4 g
*2,688Cl
Ta có
nCl2 = 0,12 mol
=>mCL2 = 0,12. 71 = 8,52g
nN2O=\(\frac{11,2}{22,4}=0,5\left(mol\right)\)
\(\Rightarrow m_{N2O}=0,5.44=22\left(g\right)\)
nSO2=\(\frac{2,24}{22,4}=0,1\left(mol\right)\)
\(\Rightarrow m_{SO2}=0,1.64=6,4\left(g\right)\)
nCl=\(\frac{2,688}{22,4}=0,12\left(mol\right)\)
\(\Leftrightarrow m_{Cl}=0,12.35,5=4,26\left(g\right)\)
