Question

Tính giá trị biểu thức:

Answer 1

\(a,\sqrt{\left(3-2\sqrt{2}\right)^2}+\sqrt{\left(3+2\sqrt{2}\right)^2}\\ =3-2\sqrt{2}+3+2\sqrt{2}=6\\ b,\sqrt{\left(\sqrt{2}+1\right)^2}-\sqrt{\left(\sqrt{2}-5\right)^2}=\sqrt{2}+1-\left(5-\sqrt{2}\right)=2\sqrt{2}-4\)

Answer 2

=\(3-2\sqrt{2}+3+2\sqrt{2}\)

=6

Answer 3

a: Ta có: \(\sqrt{\left(3-2\sqrt{2}\right)^2}+\sqrt{\left(3+2\sqrt{2}\right)^2}\)

\(=3-2\sqrt{2}+3+2\sqrt{2}\)

=6

b: Ta có: \(\sqrt{\left(\sqrt{2}+1\right)^2}-\sqrt{\left(\sqrt{2}-5\right)^2}\)

\(=\sqrt{2}+1-5+\sqrt{2}\)

\(=2\sqrt{2}-4\)

Answer 4

=\(\sqrt{2}+1-\sqrt{2}+5\)

=6