=>1+3+5+...+x=225
Số số hạng là (x-1):2+1
Tổng là: \(\dfrac{\dfrac{\left(x+1\right)\left(x-1\right)}{2}+1}{2}=\dfrac{x^2-1+2}{4}=\dfrac{x^2+1}{4}\)
=>\(\dfrac{x^2+1}{4}=225\)
\(\Leftrightarrow x^2+1=900\)
=>x2=899
hay \(x=\sqrt{899}\)
\(600-\left(1+3+5+...+x\right)=375\)
\(\Rightarrow\dfrac{\left(x-1\right):2+1}{2}\left(x+1\right)=225\)
\(\Rightarrow\dfrac{x+1}{4}\left(x+1\right)=225\)
\(\Rightarrow\left(x+1\right)^2=900\)
\(\Rightarrow x+1=30\left(x>0\right)\)
\(\Rightarrow x=29\)