\(\Leftrightarrow\left(x-3\right)\left(11-x\right)\left(11+x\right)=0\)
hay \(x\in\left\{3;11;-11\right\}\)
\(\Leftrightarrow\left(x-3\right)\left(11-x\right)\left(11+x\right)=0\)
hay \(x\in\left\{3;11;-11\right\}\)
tim x :
( 2x+3)2=9/121
( 3x-1)3=-8/27
Tìm X
e) – 40 – (– 3 – 33) + (40 – x) = – (– 47) f) x(3x – 9). (121 – x2) = 0
g) – 62 – (38 + x) + 2x = – 100 h) (x + 1)2.(x2 + 1) = 0
i) (x – 12) – (2x + 31) = 6 k) 17/ (x + 3)3 : 3 – 1 = – 10
Tìm X
e) – 40 – (– 3 – 33) + (40 – x) = – (– 47) f) x(3x – 9). (121 – x2) = 0
g) – 62 – (38 + x) + 2x = – 100 h) (x + 1)2.(x2 + 1) = 0
i) (x – 12) – (2x + 31) = 6 k) 17/ (x + 3)3 : 3 – 1 = – 10
Tìm X
e) – 40 – (– 3 – 33) + (40 – x) = – (– 47) f) x(3x – 9). (121 – x2) = 0
g) – 62 – (38 + x) + 2x = – 100 h) (x + 1)2.(x2 + 1) = 0
i) (x – 12) – (2x + 31) = 6 k) 17/ (x + 3)3 : 3 – 1 = – 10
(x2 + 9) (9x2 -1) = 0
(4x2 -9) (2x-1 -1) =0
( 3x+2) (9-x2 ) =0
(3x+3)2 ( 4x - 42 ) =0
2(x-5) ( x+2) =1
e) – 40 – (– 3 – 33) + (40 – x) = – (– 47) ; f) x(3x – 9). (121 – x2) = 0
g) – 62 – (38 + x) + 2x = – 100 ;h) (x + 1)2.(x2 + 1) = 0
i) (x – 12) – (2x + 31) = 6 ;k) 17/ (x + 3)3 : 3 – 1 = – 10
cần gấp ạ
a, (2x-121).1990=1990
b,(3x-27).2016=0
c,x.(3x-9)=0
d,(x-1).(x-5)=0
Đề bài tìm x các bạn giúp mik nha !!!
(9−x2)(3x−6)=0
a) (x-1).(x+2)=0
b) (x+4).(4-x)=0
c) (x+4)(-3x+9)=0
d) (2x-4)(x+3)=0
e) (x2-9).(2x+10)=0
g) (4-x).x2=0