\(5x=4y\Rightarrow\frac{x}{4}=\frac{y}{5}\)
Đặt \(\frac{x}{4}=\frac{y}{5}=k\Rightarrow x=4k;y=5k\)
\(\Rightarrow4k.5k=6\Rightarrow k^2=\frac{6}{20}=\frac{3}{10}\)
\(\Rightarrow k=\hept{\begin{cases}\sqrt{\frac{3}{10}}\\-\sqrt{\frac{3}{10}}\end{cases}}\)
Thay vào để tìm x ; y
\(5x=4y\Rightarrow\frac{x}{4}=\frac{y}{5}=\frac{x.y}{4.5}=\frac{6}{20}=\)\(\frac{3}{10}\)\(\Rightarrow5x=\frac{3}{10}\Rightarrow x=\frac{3}{50}\)
\(\Rightarrow4y=\frac{3}{10}\Rightarrow y=\frac{3}{40}\)
Chúc bạn hok tốt