Question

tìm x

a) (2x-5)(3x-1)=6x(x-2)

b) (x+2)(x^2x+4)-x(x^2-1)=2

c) 3x(x-1)+x-1=0

Answer 1

a: \(\Leftrightarrow6x^2-2x-15x+5=6x^2-12x\)

=>-17x+5=-12x

=>-5x=-5

=.x=1

b: \(\Leftrightarrow x^3+8-x^3+x=2\)

=>x=-6

c: =>(x-1)(3x+1)=0

=>x=1 hoặc x=-1/3

Answer 2

a, \(6x^2-17x+5=6x^2-12x\Leftrightarrow-5x=-5\Leftrightarrow x=1\)

b, \(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x^2-1\right)=2\Leftrightarrow x^3+8-x^3+x=2\Leftrightarrow x+6=0\Leftrightarrow x=-6\)

c, \(\left(3x+1\right)\left(x-1\right)=0\Leftrightarrow x=-\dfrac{1}{3};x=1\)